Wednesday, February 26, 2014

SOAP Version Mismatch: SOAP Version "SOAP 1.2 Protocol" in request does not match the SOAP version "SOAP 1.1 Protocol" of the Web service.

We were getting the below error in our project, when trying to invoke a web service.

[Server:server-one] 07:29:12,927 ERROR [stderr] (http-/ [ISS.0088.9168] SOAP Version Mismatch: SOAP Version "SOAP 1.2 Protocol" in request does not match the SOAP version "SOAP 1.1 Protocol" of the Web service.
[Server:server-one] 07:29:12,928 ERROR [stderr] (http-/   at
[Server:server-one] 07:29:12,929 ERROR [stderr] (http-/   at
[Server:server-one] 07:29:12,929 ERROR [stderr] (http-/   at
[Server:server-one] 07:29:12,929 ERROR [stderr] (http-/   at
[Server:server-one] 07:29:12,930 ERROR [stderr] (http-/   at
[Server:server-one] 07:29:12,930 ERROR [stderr] (http-/   at
[Server:server-one] 07:29:12,931 ERROR [stderr] (http-/   at

The solution lies in the configuration files used by spring.
Here in our project, the version specified in this file was 1.2 where as the web service was expecting 1.1

<bean id="messageFactory" class="">
    <property name="soapVersion">
        <util:constant static-field="" />

How to break a list into smaller sublists of equal size

// chops a list into non-view sublists of length L
static <T> List<List<T>> chopped(List<T> list, final int L) {
    List<List<T>> parts = new ArrayList<List<T>>();
    final int N = list.size();
    for (int i = 0; i < N; i += L) {
        parts.add(new ArrayList<T>(
            list.subList(i, Math.min(N, i + L)))
    return parts;

List<Integer> numbers = Collections.unmodifiableList(
List<List<Integer>> parts = chopped(numbers, 3);
System.out.println(parts); // prints "[[5, 3, 1], [2, 9, 5], [0, 7]]"
System.out.println(parts); // prints "[[5, 3, 1, -1], [2, 9, 5], [0, 7]]"
System.out.println(numbers); // prints "[5, 3, 1, 2, 9, 5, 0, 7]" (unmodified!)

Monday, February 24, 2014

Generate java classes using xjc

Source : Generate java class from xml schema using jaxb xjc command

Before using JAXB to create or access an XML document from Java application, we have to do the following steps:

1.Binding the schema
* Binding a schema means generating a set of Java classes that represents the schema for the XML document (Schema is not required for simple marshalling and unmarshalling).

2.Marshal the content tree /Unmarshal the XML document.
* After binding the schema, you can convert Java objects to and from XML document.
In this example we will see how to bind the schema. For that, we use Java Architecture for XML Binding (JAXB) binding compiler tool, xjc, to generate Java classes from XML schema.

‘xjc’ Command Line Options


xjc [-options ...] … [-b ] …
If dir is specified, all schema files in it will be compiled.
If jar is specified, /META-INF/sun-jaxb.episode binding file will be compiled.

Complete list of options for ‘xjc’ is available in the help option.

xjc -help

Generate Java classes using ‘xjc’

Follow the steps below to generate a set of Java source files from XML schema.
  1. Create a new Java project folder and name it as “JAXBXJCTool”.
  2. Create a new XSD file and name it as “employee.xsd” and copy the following lines. This is the XML schema in our example which is to be bound to java classes
  3. Employee.xsd

    <?xml version="1.0" encoding="UTF-8" standalone="yes"?>
    <xs:schema version="1.0" xmlns:xs=""> 
      <xs:element name="employee" type="employee"/> 
      <xs:complexType name="employee"> 
          <xs:element name="name" type="xs:string" minOccurs="0"/> 
          <xs:element name="salary" type="xs:double"/> 
          <xs:element name="designation" type="xs:string" minOccurs="0"/> 
          <xs:element name="address" type="address" minOccurs="0"/> 
        <xs:attribute name="id" type="xs:int" use="required"/> 
      <xs:complexType name="address"> 
          <xs:element name="city" type="xs:string" minOccurs="0"/> 
          <xs:element name="line1" type="xs:string" minOccurs="0"/> 
          <xs:element name="line2" type="xs:string" minOccurs="0"/> 
          <xs:element name="state" type="xs:string" minOccurs="0"/> 
          <xs:element name="zipcode" type="xs:long"/> 
  4. Save the file
  5. Create a new folder ‘src’ inside the project folder.
  6. In Windows open Command Prompt (Windows button + R and type cmd) or Terminal in Linux and go to the project folder (use cd command) where it exists in your machine and type the following command
  7. C:\Users\iByteCode\Desktop\JAXBXJCTool>xjc -d src -p com.theopentutorials.jaxb.beans employee.xsd
  8. This will generate set of Java source files with appropriate annotation inside ‘src’ folder

Wednesday, February 19, 2014

How to make ajax call in spring framework

Write a server side method, with a mapping something as follows:

public @ResponseBody  
String getChildren(@RequestParam(value = "ocn") String ocn, 
HttpServletRequest request, HttpServletResponse response) 
       return ocn.toUpperCase();   
Here @ResponseBody tells the framework to return value of the method to the browser and not lookup for a view with that name.
You can optionally omit request and response parameters in the signature of the method, if you like to.

After removal of request and response the method will look like

public @ResponseBody  
String getChildren(@RequestParam(value = "ocn") String ocn) 
       return ocn.toUpperCase();   

Write a javascript method as follows (This uses jquery to fire ajax request)

function populateSubAgents(obj)
    url: "getKids.html?ocn="+obj.value,
    success: function(data) {
    error: function(XMLHttpRequest, textStatus, errorThrown) { 
      if (XMLHttpRequest.status == 0) {
        alert(' Check Your Network.');
      } else if (XMLHttpRequest.status == 404) {
        alert('Requested URL not found.');
      } else if (XMLHttpRequest.status == 500) {
        alert('Internel Server Error.');
      }  else {
         alert('Unknown Error.\n' + XMLHttpRequest.responseText);