Adding a semicolon to each line where it doesn't end with semicolon
Adding a particular line before each line
I had a requirement where in the document I had lines like
D:\abc\yogesh.sql
And the requirement was to convert it into
EXECUTING yogesh.sql
D:\abc\yogesh.sql
Let me explain the regular expression
((.+)\\(.+))
\1 will represent the complete selected line i.e. D:\abc\yogesh.sql
\2 will represent the matter selected by first .+ i.e. D:\abc
\3 will represent the matter selecte dby second .+ i.e. yogesh.sql
D:\abc\yogesh.sql
And the requirement was to convert it into
EXECUTING yogesh.sql
D:\abc\yogesh.sql
Let me explain the regular expression
((.+)\\(.+))
\1 will represent the complete selected line i.e. D:\abc\yogesh.sql
\2 will represent the matter selected by first .+ i.e. D:\abc
\3 will represent the matter selecte dby second .+ i.e. yogesh.sql
Append * to end of each line
Remove * from end of each line
Change MM by dd or dd by MM in a date
Remove C++ comments from the file
This will remove the single line comments from the file
Removing the multiline comments is a 3 step process (Do the following)
Change the \r\n to a custom string of your choice (which you think is not already present in the file)
Now you have to find the string between /* and */ and replace it with empty string.
Please note that regular expressions are greedy, they'll try to match as much as they can.
For example
/th.*s/ -- This will start matching from where it finds th and it matches till the last available s.
If the string is this string matches the values
It'll match the complete string, where as the requirement was to match the only word this
http://www.regular-expressions.info/javascriptexample.html
Solution : try this /th[^s]s/ or /th.*?s/
Use the following to remove multiline comments.
Let me explain the regular expression
Another way to achieve the same effect is
\/\*.*?\*\/
Now replace mynextlineReplacementString with \r\n (while selecting Extended mode)
Removing the multiline comments is a 3 step process (Do the following)
Change the \r\n to a custom string of your choice (which you think is not already present in the file)
Now you have to find the string between /* and */ and replace it with empty string.
Please note that regular expressions are greedy, they'll try to match as much as they can.
For example
/th.*s/ -- This will start matching from where it finds th and it matches till the last available s.
If the string is this string matches the values
It'll match the complete string, where as the requirement was to match the only word this
http://www.regular-expressions.info/javascriptexample.html
Solution : try this /th[^s]s/ or /th.*?s/
Use the following to remove multiline comments.
Let me explain the regular expression
\/ # a forward slash \* # followed by an asterisk [^\*\/]+ # keep matching until you find */ i.e. end of multiline comment. \*\/ # This is to include */ as well in the selection.
Another way to achieve the same effect is
\/\*.*?\*\/
// Non-greedy quantifiers have the same syntax as regular greedy ones, // except with the quantifier followed by a question-mark. // For example, a non-greedy pattern might look like: "/A[A-Z]*?B/". // In English, this means "match an A, followed by only as many capital // letters as are needed to find a B." // One little thing to look out for is the fact that // the pattern "/[A-Z]*?./" will always match zero capital letters. // If you use non-greedy quantifiers, watch out for matching // too little, which is a symmetric danger. \/ # a forward slash \* # followed by an asterisk .*?\*\/ # match only that many characters that are required to find a */
Now replace mynextlineReplacementString with \r\n (while selecting Extended mode)
Removing the preceding numbers from each line
Removing the lines which do not contain dot (.) character